A solution of 0 . 5   g of a solute (molar mass = 150   g   mol - 1 ) in 50   g of a…

A solution of 0.5 g of a solute (molar mass =150 g mol-1) in 50 g of a solvent yields a boiling point elevation of 0.40 K. Another solution of 0.60 g of an unknown solute in the same mass of solvent exhibits a boiling point elevation of 0.8 K. The molar mass of unknown solute is :
  1. 60 g mol-1
  2. 90 g mol-1
  3. 120 g mol-1
  4. 180 g mol-1

Solution

ΔTb1ΔTb2∝m1 m2∝(moles)1(moles)2 ∵ mass of  solvent  is same 

0.400.80=0.5×x150×0.60

0.4x=36

x=90

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Asked in: JEE-TOPICTESTS-CHEMISTRY

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