A solution of 0 . 1 M weak base ( B ) is titrated with 0 . 1 M of a strong acid ( HA ) . The variation of pH…

A solution of 0.1 M weak base (B) is titrated with 0.1 M of a strong acid (HA). The variation of pH of the solution with the volume of HA added is shown in the figure below. What is the pKb of the base? The neutralization reaction is given byB+HABH++A-.

Solution

At 3 ml pH of solution is 11.

B+HABH++A

at 3 best buffer action is shown

So, POH=PKb=3 (As basic buffer is formed)

So, PKb=3

Asked in: JEE Advanced 2020 (Paper 2)

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