A solid sphere of radius R carries a positive charge Q distributed uniformly throughout its volume. A very…

A solid sphere of radius R carries a positive charge Q distributed uniformly throughout its volume. A very thin hole is drilled through it's center. A particle of mass m and charge -q performs simple harmonic motion about the center of the sphere in this hole. The frequency of oscillation is
  1. 12πQq4πε0R3 m12
  2. 12πQq4πε0R2 m12
  3. 12πQ4πε0mR3-12
  4. 12πQq4πε0mR12

Solution

Electric field inside a uniformly charged solid sphere is given by, E=Qr4πε0R3.

Therefore, the force on the negative charge -q at distance r from the centre will be F=-Qrq4πε0R3.

Comparing it with F=-kxk=Qq4πε0R3.

Now the frequency of the oscillation is f=12πkm=12πQq4πε0R3m.

Asked in: AP EAMCET 2022 (04 Jul Shift 2)

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