A solid sphere of mass 2 kg is rolling on a frictionless horizontal surface with velocity 6 m s - 1 . It collides on the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring = 36 N m - 1 ).

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Aicharya · Accepted Answer

Kinetic energy of rolling solid sphere = 1 2 m V 2 + 1 2 I &#969; 2 = 1 2 m V 2 + 1 2 &#215; 2 5 m r 2 &#969; 2 = 1 2 m V 2 + 1 5 m V 2 = 7 10 m V 2 The potential energy of the spring on maximum compression x = 1 2 k x 2 &#8756; &#160; &#160; &#160; &#160; 1 2 k x 2 = 7 10 m V 2 x 2 = 14 10 m V 2 k = 14 10 &#215; 2 6 2 36 &#160; &#160; = 2.8 x = 2.8 &#160;m *

A solid sphere of mass 2 kg is rolling on a frictionless horizontal surface with velocity 6 m s - 1 . It…

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