A solid sphere of lithium is rotating with angular frequency ' $\omega$ ' about an axis passing through its…

A solid sphere of lithium is rotating with angular frequency ' $\omega$ ' about an axis passing through its diameter. If its temperature is raised by $50^{\circ} \mathrm{C}$ then its new angular frequency is $\left(\alpha_{\text {lithium }}=60 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)$
  1. $0.99 \omega$
  2. $0.73 \omega$
  3. $0.83 \omega$
  4. $0.94 \omega$

Solution

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Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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