A solid sphere is rolling on a surface as shown in figure, with a translational velocity $v \mathrm{~m}…

A solid sphere is rolling on a surface as shown in figure, with a translational velocity $v \mathrm{~m} \mathrm{~s}^{-1}$. If it is to climb the inclined surface continuing to roll without slipping, then minimum velocity for this to happen is
  1. $\sqrt{2 g h}$
  2. $\sqrt{\frac{7}{5} g h}$
  3. $\sqrt{\frac{7}{2} g h}$
  4. $\sqrt{\frac{10}{7} g h}$

Solution

Minimum velocity for a body rolling without slipping $ v=\sqrt{\frac{2 g h}{1+\frac{K^2}{R^2}}} $ For solid sphere, $\frac{K^2}{R^2}=\frac{2}{5}$ $ \therefore \quad v=\sqrt{\frac{2 g h}{1+\frac{K^2}{R^2}}}=\sqrt{\frac{10}{7} g h} $

Asked in: JEE Main 2012 (12 May Online)

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