A solid sphere has mass ' $M$ ' and radius ' $R$ '. Its moment of inertia about a parallel axis passing…
A solid sphere has mass ' $M$ ' and radius ' $R$ '. Its moment of inertia about a parallel axis passing through a point at a distance $\frac{R}{2}$ from its centre is
$\frac{8 \mathrm{MR}^2}{11}$
$\frac{11 \mathrm{MR}^2}{18}$
$\frac{7 \mathrm{MR}^2}{10}$
$\frac{13 \mathrm{MR}^2}{20}$
Solution
Concept: Parallel axis theorem application.
The moment of inertia for a sphere about the central rotation axis is:
$\mathrm{I}_{\text {sphere }}=\frac{2}{5} \mathrm{MR}^2$
See the diagram below,
To find the moment of inertia about the new rotation axis we use parallel axis theorem:
To find the moment of inertia about the new rotation axis we use parallel axis theorem: