A solid copper cube of $7 \mathrm{~cm}$ edge is subjected to a hydraulic pressure of $8000 \mathrm{kPa}$. The volume contraction of the copper cube is (Bulk modulus of copper $=140 \mathrm{GPa}$ )

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Aicharya · Accepted Answer

Given, edge of solid copper cube, $l=7 \mathrm{~cm}$ hydraulic pressure, $p=8000 \mathrm{kPa}=8000 \times 10^3 \mathrm{~Pa}$ and Bulk modulus of copper, $\beta=140 \mathrm{GPa}$ $=140 \times 10^9 \mathrm{~Pa}$ As we know that, $\begin{aligned} & \text {Bulk modulus, } \beta=\frac{p}{\left(\frac{\Delta V}{V}\right)} \text { or } \beta=\frac{p V}{\Delta V} \ & \begin{aligned} \therefore \Delta V=\frac{p V}{\beta} & =\frac{8000 \times 10^3 \times(l)^3}{140 \times 10^9} \ & =\frac{8000 \times 10^3 \times(7)^3}{140 \times 10^9}=19.6 \times 10^{-3} \mathrm{~cm}^3 \end{aligned} \end{aligned}$

A solid copper cube of \(7 \mathrm{~cm}\) edge is subjected to a hydraulic pressure of \(8000 \mathrm{kPa}\)…

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