A solid conducting sphere of radius a has a net positive charge $2 Q$. A conducting spherical shell of inner…

A solid conducting sphere of radius a has a net positive charge $2 Q$. A conducting spherical shell of inner radius $\mathrm{b}$ and outer radius $\mathrm{c}$ is concentric with the solid sphere and has a net charge $-$ Q.The surface charge density on the inner and outer surfaces of the spherical shell will be
  1. $-\frac{2 Q}{4 \pi b^{2}}, \frac{Q}{4 \pi c^{2}}$
  2. $-\frac{Q}{4 \pi b^{2}}, \frac{Q}{4 \pi c^{2}}$
  3. $0, \frac{Q}{4 \pi c^{2}}$
  4. None of the above

Solution

Surface charge density $(\sigma)=\frac{\text { Charge }}{\text { Surface area }}$
So $\sigma_{\text {inner }}=\frac{-2 Q}{4 \pi b_{Q}^{2}}$
and $\sigma_{\text {Outer }}=\frac{Q}{4 \pi c^{2}}$

Asked in: JEE Mains - Electrostatics - Test 2

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