A solenoid having 400 turns per metre has a core of a material with relative permeability 400. When a…

A solenoid having 400 turns per metre has a core of a material with relative permeability 400. When a current of 0.5 A is passed through it, the magnetization of the core material in $\mathrm{Am}^{-1}$ is nearly
  1. $6 \times 10^5$
  2. $6 \times 10^4$
  3. $8 \times 10^5$
  4. $8 \times 10^4$

Solution

Magnetic intensity, $\mathrm{H}=\mathrm{nI}=400 \times 0.5=200 \mathrm{Am}^{-1}$ $\mu_{\mathrm{r}}=1+\chi \Rightarrow \chi=\left(\mu_{\mathrm{r}}-1\right)$ $\begin{aligned} \therefore \quad \mathrm{M}=\chi \mathrm{H} & =\left(\mu_{\mathrm{r}}-1\right) \mathrm{H}=(400-1) \times 200 \\ & =7.98 \times 10^4 \mathrm{Am}^{-1} \\ & \approx 8 \times 10^4 \mathrm{Am}^{-1}\end{aligned}$

Asked in: MHT CET 2024 (16 May Shift 2)

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