A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The…

A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm . The magnifying power of telescope for viewing a distant object is:
  1. 28
  2. 17
  3. 32
  4. 34

Solution

$f_0=140 \mathrm{~cm}$ and $f_e=5 \mathrm{~cm}$ For distant object, $m=\frac{f_0}{f_e}=\frac{140}{5}=28$

Asked in: NEET 2024

Practice more Optics questions on Aicharya