A small sphere is hung by a string fixed to a wall as shown in the figure. The sphere is pushed from the wall by a stick. The forces acting on the sphere are as shown. Then, identify the incorrect expression.

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Aicharya · Accepted Answer

$\begin{aligned} & 	ext { i.e., } \Sigma F_x=0 \ & \Rightarrow \quad P-T \sin 	heta=0\end{aligned}$ $P=T \sin 	heta$ ...(i) and $\quad \Sigma F_y=0$ $\Rightarrow \quad W-T \cos 	heta=0$ $W=T \cos 	heta$ ...(ii) By dividing Eq. (i) by Eq. (ii), we get $\frac{P}{W}=\frac{T \sin 	heta}{T \cos 	heta}$ $\Rightarrow \quad P=W 	an 	heta$ and their vector sum is also zero. i.e. $\quad \mathbf{T}+\mathbf{P}+\mathbf{W}=0$ Resultant of $P$ and $W$ is also equal and opposite to tension $T$ $	herefore \quad T^2=P^2+w^2$ That's why, equation $T=P+W$ is the only incorrect expression.

A small sphere is hung by a string fixed to a wall as shown in the figure. The sphere is pushed from the…

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