A small object is enclosed in a transparent solid sphere of radius 8   cm . The object is situated at 2…

The figure below represents transparent solid sphere.

From the figure,

$u=-6 \mathrm{cm}$

$v=-3.2 \mathrm{cm}$

The formula for the refractive indexes of first and second
medium with respect to air,

$\frac{{\mu }_2}{v}-\frac{{\mu }_1}{u}=\left(\frac{{\mu }_2-{\mu }_1}{R}\right)$

Substitute the values in the above equation.

$\frac{1}{-3.2}-\frac{\mu }{-6}=\left(\frac{1-\mu }{-8}\right)$

Simplify the above equation.

$\mu =1.5$