A small hole is made in a circular disc of mass ' $M$ ' and radius ' $R$ ' at a distance of $\frac{R}{4}$…

A small hole is made in a circular disc of mass ' $M$ ' and radius ' $R$ ' at a distance of $\frac{R}{4}$ from the centre. The disc is supported on a horizontal peg through this hole. The moment of inertia of the disc about the horizontal peg is
  1. $\frac{9 \mathrm{MR}^2}{16}$
  2. $\frac{5 \mathrm{MR}^2}{4}$
  3. $\frac{5 \mathrm{MR}^2}{16}$
  4. $\frac{\mathrm{MR}^2}{9}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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