A small block slides down from the top of hemisphere of radius $R = 3 m$ as shown in the figure. The height $h$ at which the block will lose contact with the surface of the sphere is $m$ . (Assume there is no friction between the block and the hemisphere)

Question

Aicharya · Accepted Answer

m g cos &#952; = m v 2 R &#160; &#160; &#160; . . . ( 1 ) cos &#952; = h R Energy conservation m g { R - h } = 1 2 m v 2 . . . ( 2 ) from ( 1 ) and ( 2 ) &#160; &#8658; m g h R = 2 m g { R - h } R h = 2 R 3 = 2 &#160; m

A small block slides down from the top of hemisphere of radius R = 3   m as shown in the figure. The…

Solution

A small block slides down from the top of hemisphere of radius R = 3 &#160; m as shown in the figure. The…

Solution

A small block slides down from the top of hemisphere of radius R = 3 m as shown in the figure. The…