A siren emitting a sound of frequency $800\text{ Hz}$ moves away from an observer towards a cliff at a speed…
A siren emitting a sound of frequency $800\text{ Hz}$ moves away from an observer towards a cliff at a speed of $15\text{ ms}^{-1}$. Then, the frequency of sound that the observer hears in the echo reflected from the cliff is (Take, velocity of sound in air $= 330\text{ ms}^{-1}$) [NEET 2016]
800 Hz
838 Hz
885 Hz
765 Hz
Solution
The given situation can be shown as below.
[An observer stands behind a source moving at $15\text{ ms}^{-1}$ towards a cliff.]
Frequency of sound that the observer hear in the echo reflected from the cliff is given by
$f' = \left(\frac{v}{v - v_s}\right)f$
where, $f =$ original frequency of source,
$v =$ velocity of sound
and $v_s =$ velocity of source.
So, $f' = \left(\frac{330}{330 - 15}\right) 800 = 838.09\text{ Hz} \approx 838\text{ Hz}$