A simple harmonic oscillator consists of a particle of mass $m$ and an ideal spring with spring constant $k$…

A simple harmonic oscillator consists of a particle of mass $m$ and an ideal spring with spring constant $k$. The particle oscillates with a time period $T$. The spring is cut into two equal parts. If one part oscillates with the same particle, the time period will be
  1. $2 T$
  2. $\sqrt{2} T$
  3. $\frac{T}{\sqrt{2}}$
  4. $\frac{T}{2}$

Solution

Mass of the particle $=m$ spring constant $=k$ The time period of oscillator, $T=2 \pi \sqrt{\frac{m}{k}}$ As $k \propto \frac{1}{l}$ (where $l$ is the length of spring) $\begin{array}{rlrl} \because & k^{\prime} & =2 k \\ & \therefore & T^{\prime} & =2 \pi \sqrt{\frac{m}{2 k}}=\frac{1}{\sqrt{2}} T \end{array}$

Asked in: AP EAMCET 2011

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