(A) Show how you would connect three resistors each of resistance 6 Ω, so that the combination has a…
(A) Show how you would connect three resistors each of resistance 6 Ω, so that the combination has a resistance of 9 Ω. Also justify your answer.
OR
(B) In the given circuit calculate the power consumed in watts in the resistor of 2 Ω :
Solution
(A) When two 6 Ω resistances are connected in parallel and the third resistance of 6Ω is connected in series combination to this, then equivalent resistance will be 9 Ω /
[circuit diagram: 6Ω and 6Ω in parallel, in series with a third 6Ω, between points A and B]
[Award marks for writing the statement or drawing the diagram]
$\dfrac{1}{Rp}$ = 1/6Ω + 1/6Ω
∴ Rp = 3Ω
Rs = 6 + 3 = 9Ω
