A short magnet oscillates with a frequency $10 \mathrm{~Hz}$ where horizontal component of Earth's magnetic…

A short magnet oscillates with a frequency $10 \mathrm{~Hz}$ where horizontal component of Earth's magnetic field is $12 \mu \mathrm{T}$. A downward current of $15 \mathrm{~A}$ is established in a vertical wire placed $20 \mathrm{~cm}$ west of the magnet. The new frequency of the magnet is
  1. $4 \mathrm{~Hz}$
  2. $2.5 \mathrm{~Hz}$
  3. $9 \mathrm{~Hz}$
  4. $5 \mathrm{~Hz}$

Solution

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Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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