A short electric dipole has a dipole moment of $16 \times 10^{- 9} C m$ . The electric potential due to the dipole at a point at a distance of $0.6 m$ from the centre of the dipole, situated on a line making an angle of $60 °$ with the dipole axis is:
$(\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N m^{2} C^{- 2})$

Question

A short electric dipole has a dipole moment of

16 \times 10^{- 9} C m

. The electric potential due to the dipole at a point at a distance of

0.6 m

from the centre of the dipole, situated on a line making an angle of

60 °

with the dipole axis is:

(\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N m^{2} C^{- 2})

Aicharya · Accepted Answer

We know that, Electric dipole potential, V = 1 4 π ε ∘ p c o s θ r 2 , for large distance of r . V = k P cos θ r 2 = 9 × 10 9 × 16 × 10 − 9 ( 0 .6 ) 2 × 1 2 V = 200 V *

A short electric dipole has a dipole moment of 16 × 10 – 9 C m . The electric potential due to the dipole at…

Solution