A series LCR circuit of R = 5   Ω ,   L = 20   mH and C = 0 . 5   μ F is…

A series LCR circuit of R=5 Ω, L=20 mH and C=0.5 μF is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is ________×102 W.

Solution

XL=XC (due to resonance)

Z=R so irms=VZ=VR

V2R=250×2505=125×102 W

Asked in: JEE Main 2021 (20 Jul Shift 2)

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