A self-fertilizing trihybrid plant forms:

A self-fertilizing trihybrid plant forms:
  1. 8 different gametes and 64 different zygotes
  2. 4 different gametes and 16 different zygotes
  3. 8 different gametes and 16 different zygotes
  4. 8 different gametes and 32 different zygotes.

Solution

The genotype of trihybrid would be $\mathrm{AaBbCc}$. Number of gametes $=$ (no. of genes studied) ${ }^n$ Where $n=$ no. of heterozygous alleles Thus, Number of gametes $=(2)^3=8$ No. of Zygotes $=(2)^{2 \mathrm{n}}=(2)^{2 \times 3}=(2)^6$ $=64$

Asked in: NEET 2004

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