A screen is placed $100 \mathrm{~cm}$ from an object. The image of the object on the screen is formed by a…

A screen is placed $100 \mathrm{~cm}$ from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by $20 \mathrm{~cm}$. The focal length of the lens is
  1. $18 \mathrm{~cm}$
  2. $24 \mathrm{~cm}$
  3. $25 \mathrm{~cm}$
  4. $30 \mathrm{~cm}$

Solution

Given, distance between screen and object, $d=100 \mathrm{~cm}$ Separation between the two pośitions of convex lens, $\quad x=20 \mathrm{~cm}$ focal length of the lens, $f=\frac{d^2-x^2}{4 d}$ $ \begin{aligned} & =\frac{(100)^2-(20)^2}{4 \times 100} \\ & =\frac{10000-400}{400}=\frac{9600}{400} \\ & =24 \mathrm{~cm} \end{aligned} $

Asked in: AP EAMCET 2022 (06 Jul Shift 2)

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