A scooter accelerates from rest for time t 1 at constant rate a 1 and then retards at constant rate a 2 for…

A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t1t2 will be :
  1. a2a1

  2. a1a2
  3. a1+a2a1
  4. a1+a2a2

Solution

Draw vt curve 

tanθ1=a1=vmaxt1
& tanθ2=a2=vmaxt2
÷ above

t1t2=a2a1

Asked in: JEE Main 2021 (26 Feb Shift 2)

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