A satellite revolving around a planet has orbital velocity $10 \mathrm{~km} / \mathrm{s}$. The additional…
A satellite revolving around a planet has orbital velocity $10 \mathrm{~km} / \mathrm{s}$. The additional velocity required for the satellite to escape from the gravitational field of the planet is
$14.14\ km/s$
$11.2\ km/s$
$4.14\ km/s$
$41.4\ km/s$
Solution
The relation between two velocities is given by the relation
$\begin{aligned}
& v_{\mathrm{e}}=(\sqrt{2}-1) v_0 \\
& =(1.414-1) \mathrm{v}_0 \\
& =0.414 \times 10=4.14 \mathrm{~km} / \mathrm{s}
\end{aligned}$