A satellite of mass M is launched vertically upwards with an initial speed u from the surface of the earth.…

A satellite of massM  is launched vertically upwards with an initial speed u from the surface of the earth. After it reaches height R ( R= radius of the earth), it ejects a rocket of mass M10 so that subsequently the satellite moves in a circular orbit. The kinetic energy of the rocket is ( G is the gravitational constant; Me is the mass of the earth):
  1. M20u2+113200GMeR
  2. 5Mu2-119200GMeR
  3. 3M8u+5GMe6R2
  4. M20u-2GMe3R2

Solution

-GMeMR+12Mu2=-GMeM2R+12Mv2

 

v=u2-GMeR

Vτ Transverse velocity of rocket 
VR Radial velocity of rocket

V=GMe2R

M10VT=9M10GMe2R
M10Vr=Mu2-GMeR

Kinetic energy =12M10VT2+Vr2=M2081GMe2R+100u2-100GMeR

=M20100u2-119GMe2R
=5Mu2-119GMe200R

Asked in: JEE Main 2020 (07 Jan Shift 1)

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