A satellite of mass m is orbiting the earth (of radius R ) at a height h from its surface. The total energy…

A satellite of mass m is orbiting the earth (of radius R ) at a height h from its surface. The total energy of the satellite in terms of g o , the value of acceleration due to gravity at the earth's surface, is
  1. mg0R22R+h
  2. -mg0R22R+h
  3. 2mg0R2R+h
  4. -2mg0R2R+h

Solution

The total energy of a satellite in the orbit is

E=-GMm2r

r=R+h

g0=GMR2
⇒E=-mg0R22R+h

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Asked in: NEET 2016 (Phase 2)

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