A satellite is launched into a circular orbit of radius ' R ' around the earth. A second satellite is launched into an orbit of radius 1.03 R. The time period of revolution of the second satellite is larger than the first one approximately by

Question

Aicharya · Accepted Answer

$T_1 \propto(R)^{3 / 2}$ and $T_2 \propto(1.03 R)^{3 / 2}$ $\Rightarrow \quad T_2=(1.03 R)^{3 / 2} \cdot T_1 \approx 1.045 T_1$ So $T_2$ will larger by $4.5 \%$ w.r.t. $T_1$.

A satellite is launched into a circular orbit of radius ' R ' around the earth. A second satellite is…

Solution