A sample of an ideal gas is taken through the cyclic process $a b c a$ as shown in the figure. The change in the internal energy of the gas along the path $c a$ is $- 180 J .$ The gas absorbs $250 J$ of heat along the path $a b$ and $60 J$ along the path $b c$ . The work done by the gas along the path $a b c$ is:

Question

A sample of an ideal gas is taken through the cyclic process

a b c a

as shown in the figure. The change in the internal energy of the gas along the path

c a

is

- 180 J .

The gas absorbs

250 J

of heat along the path

a b

and

60 J

along the path

b c

. The work done by the gas along the path

a b c

is:

Aicharya · Accepted Answer

In a cyclic process, Δ U = 0 From 1st law of thermodynamics Q = Δ U + W Q = W Q a b + Q b c + Q c a = W a b c + W c a W a b c = Q a b + Q b c + Q c a - W c a W a b c = Q a b + Q b c + U c a W a b c = 250 + 60 - 180 = 130 J

A sample of an ideal gas is taken through the cyclic process a b c a as shown in the figure. The change in…

Solution