A salary increases by $10\%$ in year 1 and by $20\%$ in year 2. The total percentage increase over the two…
A salary increases by $10\%$ in year 1 and by $20\%$ in year 2. The total percentage increase over the two years is
- $30\%$
- $32\%$
- $33\%$
- $200\%$
Solution
Net factor $= 1.10 \times 1.20 = 1.32$, i.e., a $32\%$ increase. Equivalent shortcut: $10 + 20 + \dfrac{10 \cdot 20}{100} = 32$.
Asked in: IMO
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