A rubber ball is released from a height of 5   m above the floor. It bounces back repeatedly, always…

A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to 81100 of the height through which it falls. Find the average speed of the ball. (Take g=10 m s-2)
  1. 3.0 m s-1
  2. 3.5 m s-1
  3. 2.0 m s-1
  4. 2.50 m s-1

Solution

v0=2gh

v=e2gh=2gh

⇒e=0.9

S=h+2e2h+2e4h+………

t=2h g+2e2h g+2e22h g+………

vav=st=2.5 m s-1

Asked in: JEE Main 2021 (17 Mar Shift 2)

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