A rubber ball be taken in a deep sea so that its volume is decreased by $x \%$. The bulk modulus of rubber…
A rubber ball be taken in a deep sea so that its volume is decreased by $x \%$. The
bulk modulus of rubber is 'K' and density of sea water is ' $\varrho$ '. The depth to which a rubber ball is taken is proportional to $(\mathrm{g}=$ acceleration due to gravity)
$\frac{\rho\text {x}}{\mathrm{Kg}}$
$\frac{\mathrm{Kx}}{\rho\mathrm{g}}$
$\frac{\rho\mathrm{g}}{\mathrm{Kx}}$
$\frac{\mathrm{Q}}{\mathrm{Kxg}}$
Solution
$B=-\frac{\Delta p}{\Delta v / v}$
$\frac{\Delta v}{v}=\frac{x}{100}...(1)$
$\Delta p=\rho g h$
$\frac{\rho g h}{x / 100}$
$h \propto \frac{k x}{\rho g}$