A rod C D of thermal resistance 10 . 0 KW - 1 is joined at the middle of an identical rod A B as shown in…

A rod CD of thermal resistance 10.0KW-1 is joined at the middle of an identical rod AB as shown in figure. The ends A, B and D are maintained at 200°C,100°C and 125°C respectively. The heat current in CD is P W. The value of P is

Solution

 

QAC+QDC=QCB

KA(200-t)2+KA(125-t)=(t-100)KA2

400-2t+125-t=2t-200

725=5t

t=145ºC

QCD=KA(145-125)=20KA=2 W

Asked in: JEE Main 2021 (27 Aug Shift 1)

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