A rhombus-shaped tile has diagonals $0.6$ m and $0.8$ m. How many such tiles are needed to cover a $24…
A rhombus-shaped tile has diagonals $0.6$ m and $0.8$ m. How many such tiles are needed to cover a $24 \text{ m}^{2}$ floor?
- $50$
- $100$
- $80$
- $200$
Solution
Area of one tile $= \dfrac{1}{2}\times 0.6 \times 0.8 = 0.24 \text{ m}^{2}$. Number of tiles $= \dfrac{24}{0.24} = 100$.
Asked in: IMO
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