A resistor has bands with colours orange, green, silver and gold. Then, the resistance of the resistor is
- $(350 \pm 5) \mathrm{m} \Omega$
- $(350 \pm 17.5) \mathrm{m} \Omega$
- $(35 \pm 5 \%) \mathrm{m} \Omega$
- $(250 \pm 5 \%) \mathrm{m} \Omega$
Solution
Given, orange $=3$, Green $=5$ Silver $=10^{-2}$ Gold (tolerance) $= \pm 5 \%$ From colour code, resistance value is $ \left[35 \times 10^{-2} \pm 5 \%\right. \text { ] } $ $ \begin{aligned} & =350 \times 10^{-3} \pm 5 \% \mathrm{ohms} \\ & =350 \mathrm{~m}-\Omega \pm 17.5 \mathrm{~m}-\Omega \end{aligned} $
Asked in: AP EAMCET 2018 (22 Apr Shift 2)