A $10 \Omega$ resistance, $5 \mathrm{mH}$ coil and $10 \mu \mathrm{F}$ capacitor are joined in series. When…

A $10 \Omega$ resistance, $5 \mathrm{mH}$ coil and $10 \mu \mathrm{F}$ capacitor are joined in series. When alternating current source of suitable frequency is joined to this combination, the circuit resonates. If the resistance is halved, the resonant frequency is
  1. quadrupled.
  2. halved.
  3. doubled.
  4. remains unchanged.

Solution

Concept based. At resonance, in LCR circuit inductive and capacitive reactance are equal: $\begin{aligned} & X_L=X_C \\ & \Rightarrow 2 \pi \mathrm{fL}=\frac{1}{2 \pi \mathrm{fC}} \\ & \Rightarrow \mathrm{f}^2=\left(\frac{1}{4 \pi^2 \mathrm{LC}}\right) \end{aligned}$ The resonant frequency is independent of the resistance.

Asked in: MHT CET 2022 (08 Aug Shift 2)

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