A remote-sensing satellite of earth revolves in a circular orbit at a height of $0.25 \times 10^{6}$ m above the surface of earth. If earth's radius is $6.38 \times 10^{6} m$ and $g = 9.8 m s^{- 2}$ , then the orbital speed of the satellite is:
Mass of earth undefined

Question

A remote-sensing satellite of earth revolves in a circular orbit at a height of

0.25 \times 10^{6}

m above the surface of earth. If earth's radius is

6.38 \times 10^{6} m

and

g = 9.8 m s^{- 2}

, then the orbital speed of the satellite is:
Mass of earth undefined

Aicharya · Accepted Answer

V 0 = G M r = G M R 2 . R 2 r = 9.8 × 6.38 × 6.38 6.63 × 10 6 = 60 × 10 6 m/sec = 7.76 km/sec .

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25 × 10 6 m above the…