A refrigerator with coefficient of performance 0 . 25 releases 250   J of heat to a hot reservoir. The…

A refrigerator with coefficient of performance 0.25 releases 250 J of heat to a hot reservoir. The work done on the working substance is
  1. 1003J
  2. 150J
  3. 200J
  4. 50J

Solution

Given, Coefficient of performance, Q2W=0.25=14

⇒Q2=W4

Q1=Q2+W

⇒Q1=W4+W

⇒W=25045=200 J

Asked in: AP EAMCET 2021 (19 Aug Shift 2)

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