A rectangular loop of length 2 . 5 m and width 2 m is placed at 60 ° to a magnetic field of 4 T . The loop…

A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is
  1. -2 V
  2. +2 V
  3. +1 V
  4. -1 V

Solution

The formula to calculate the change in the magnetic flux associated with the given loop can be written as

ϕ=-BAcosθ=-Blbcosθ   ...1

The formula to calculate the induced emf is given by

ε=-ϕt=Blbcosθt   ...2

From equation (2), it follows that

ε=4×2.5×2×cos60°10 V=1 V

Asked in: JEE Main 2024 (27 Jan Shift 1)

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