A reaction of 0.1 mole of Benzylamine with bromomethane gave $23 g$ of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times 10^{- 1},$ when $n =$ _____ (Round off to the Nearest Integer).
$(Given : Atomic masses : C : 12.0 u, H : 1.0 u, N : 14.0 u, Br : 80.0 u)$

Question

A reaction of 0.1 mole of Benzylamine with bromomethane gave

23 g

of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are

n \times 10^{- 1},

when

n =

_____ (Round off to the Nearest Integer).

(Given : Atomic masses : C : 12.0 u, H : 1.0 u, N : 14.0 u, Br : 80.0 u)

Aicharya · Accepted Answer

no of moles = 3 &#160; &#215; 10 - 1 &#160; mol

A reaction of 0.1 mole of Benzylamine with bromomethane gave 23   g of Benzyl trimethyl ammonium…