A reaction having equal energies of activation for forward and reverse reactions has
- $\Delta S=0$
- $\Delta G=0$
- $\Delta H=0$
- $\Delta H=\Delta G=\Delta S=0$
Solution

So, \(\left(E_2\right)_b=\left(E_2\right)_f+\Delta H\left(\right.\) as, \(\left(E_2\right)_b=\left(E_2\right)_f\)
So, \(\Delta H=0\). [Here $\left(E_2\right)_b=$ activation energy of backward reaction and $\left(E_2\right)_f=$ activation energy of forward reaction].
Asked in: NEET 2013 (All India)