A ray of light travels from an optically denser to rarer medium. The critical angle for the two media is '…
- $\frac{\pi}{2}-C$
- $2 C$
- $\pi-2 C$
- $\pi-C$
Solution

The deviation is given by $\begin{aligned} & \delta=\pi-2 \mathrm{i} \\ & \text { At } \mathrm{i}=\mathrm{C}, \delta=\delta_{\max } \\ & \therefore \quad \delta_{\max }=\pi-2 \mathrm{c} \end{aligned}$
Asked in: AP EAMCET 2024 (21 May Shift 1)