A ray of light through 2 , 1 is reflected at a point P on the y - axis and then passes through the point 5 ,…

A ray of light through 2,1 is reflected at a point P on the y- axis and then passes through the point 5,3. If this reflected ray is the directrix of an ellipse with eccentricity 13 and the distance of the nearer focus from this directrix is 853, then the equation of the other directrix can be:
  1. 11x+7y+8=0 or 11x+7y-15=0
  2. 11x-7y-8=0 or 11x+7y+15=0
  3. 2x-7y+29=0 or 2x-7y-7=0
  4. 2x-7y-39=0 or 2x-7y-7=0

Solution

The reflected point of 2,1 is -2,1.

Equation of reflected ray

y-1=3-15+2x+2

y-1=27x+2

7y-7=2x+4

2x-7y+11=0

Let the equation of other directrix is

2x-7y+λ=0

Distance of directrix from focus

ae-ae=853, where e is the eccentricity

3a-a3=853 or a=353

Distance from other focus ae+ae

=3a+a3=10a3=103×353=1053

Distance between two directrix =2ae

=2×3×353=1853

So, λ-1153=1853

λ-11=18 or -18

2x-7y-7=0 or 2x-7y+29=0

Asked in: JEE Main 2021 (27 Jul Shift 1)

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