A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to $60^{\circ}$. The refractive index of the prism material is $\sqrt{2}$. The angle of incidence (in degrees) is ______.

Question

Aicharya · Accepted Answer

$\begin{aligned} & \mu=\frac{\sin \left(\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}ight)}{\sin \left(\frac{\mathrm{A}}{2}ight)}, 	ext { since } \mathrm{A}=60^{\circ} \quad 	herefore \delta \mathrm{m}=30^{\circ} \ & \delta_{\mathrm{m}}=2 \mathrm{i}-\mathrm{A}[	ext { as } \mathrm{i}=\mathrm{e}] \ & \Rightarrow \mathrm{i}=45^{\circ}\end{aligned}$

A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to…

Solution