A ray of light passes through equilateral prism such that the angle of incidence is equal to angle of…

A ray of light passes through equilateral prism such that the angle of incidence is equal to angle of emergence and each of these angles is equal to $\left(\frac{3}{4}\right)^{\mathrm{th}}$ the angle of prism. The angle of deviation is
  1. $35^{\circ}$
  2. $40^{\circ}$
  3. $20^{\circ}$
  4. $30^{\circ}$

Solution

Let the angle of incidence of light at prism. $\mathrm{i}=\mathrm{x}$ So, Angle of emergence , $\mathrm{e}=\mathrm{x}$ Angle of prism, $A=\frac{4}{3} x$ Since prism is equilateral $\Rightarrow 3 \mathrm{~A}=180^{\circ} \Rightarrow \mathrm{x}=45^{\circ}$ From prism formula: Angle of deviation, $\delta=\mathrm{i}+\mathrm{e}-\mathrm{A}=45+45-60=30^{\circ}$

Asked in: MHT CET 2020 (15 Oct Shift 2)

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