A ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of…
- $45^{\circ}$
- $39^{\circ}$
- $20^{\circ}$
- $30^{\circ}$
Solution
Relation among the $(i),(e),(A)$ and $(\delta)$ $i+e=A+\delta$ $\frac{3}{4} \times 60^{\circ}+\frac{3}{4} \times 60^{\circ}=60^{\circ}+\delta$ or $\quad 45^{\circ}+45^{\circ}=60^{\circ}+\delta$ or $\delta=30^{\circ}$ where, $i=$ angle of incidence $e =\text { angle of emergence }$ $A =\text { angle of prism }$ $\delta =\text { angle of deviation }$
Asked in: AP EAMCET 2010