A ray of light is incident on the surface of a glass plate of refractive index \(\sqrt{3}\) at the…

A ray of light is incident on the surface of a glass plate of refractive index \(\sqrt{3}\) at the polarising angle. The angle of refraction of the ray is
  1. \(30^{\circ}\)
  2. \(45^{\circ}\)
  3. \(60^{\circ}\)
  4. \(37^{\circ}\)

Solution

Given, refractive index of glass plate, \(\mu=\sqrt{3}\) Polarising angle \(\theta\) of incident light is given as, \(\mu=\tan \theta\) or \(\sqrt{3}=\tan \theta \text { or } \theta=\tan ^{-1}(\sqrt{3})\) \(\therefore\) angle of incident, \(\theta=60^{\circ}\) \([\because \tan 60=\sqrt{3}]\) refractive index is given as, \(\mu=\frac{\sin i}{\sin r}\) or \(\sqrt{3} \sin r=\sin 60^{\circ} \quad \left[\because i=\theta=60^{\circ}\right]\) or \(\sqrt{3} \sin r=\frac{\sqrt{3}}{2} \text { or } \sin r=\frac{1}{2}\) or \(r=\sin ^{-1}\left(\frac{1}{2}\right) \Rightarrow r=30^{\circ}\) Thus, the angle of refraction of the ray is \(30^{\circ}\).

Asked in: AP EAMCET 2019 (22 Apr Shift 1)

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