A ray of light is incident normally on a glass slab of thickness $5 \mathrm{~cm}$ and refractive index 1.6.…
- 12 cm
- 24 cm
- 5 cm
- 8 cm
Solution
Given: $\mathrm{t}_{\mathrm{SA}}=\mathrm{t}_{\mathrm{SB}}$
$\begin{aligned}
& \mathrm{t}_{\mathrm{SA}}=\frac{\mathrm{d}}{\mathrm{c}}=\frac{1}{\left(\frac{\mathrm{C}}{\mu}\right)} \\
& \Rightarrow \mathrm{d}=\mu \mathrm{l}=1.6 \times 5 \mathrm{~cm}=8 \mathrm{~cm}
\end{aligned}$Asked in: MHT CET 2022 (08 Aug Shift 2)