A random variable X has the following probability distribution: X : 1 2 3 4 5 P X :   k 2 2 k k 2 k 5 k…

A random variable X has the following probability distribution:
X:12345PX: k22kk2k5k2
Then, PX>2 is equal to:
  1. 712
  2. 136
  3. 16
  4. 2336

Solution

W e know Pi=16k2+5k=1

6k2+5k-1=0

6k2+6k-k-1=0

6k-1k+1=0k=-1 (rejected) ; k=16

PX>2=k+2k+5k2

=16+26+536=6+12+536=2336

Asked in: JEE Main 2020 (09 Jan Shift 2)

Practice more Probability questions on Aicharya