A radioactive nucleus A Z X undergoes spontaneous decay in the sequence A Z X → Z - 1 B → Z - 3 C → Z - 2 D …

A radioactive nucleus AZX undergoes spontaneous decay in the sequence AZX→Z-1B→Z-3C→Z-2D, where Z is the atomic number of element X. The possible decay particles in the sequence are:
  1. α,β-,β+
  2. α,β+,β-
  3. β+,α,β-
  4. β-,α,β+

Solution

As we know due to α-decay atomic number decreases by 2 and mass no. decreases by 4 . And due to β-decay mass no. remain unchanged and atomic no. increases by 1 And due to β+decay mass no. remain unchanged but atomic no. decreases by 1.

So, option (3) is correct option.

Asked in: NEET 2021

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